# What is the vertex form of y= 4x^2 - 8x + 3 ?

$y = 4 {\left(x - 1\right)}^{2} - 1$
Vertex form is $y = {\left(a x + b\right)}^{2} + c$ . In this case $a = 2$ and $b = - 2$
${\left(2 x - 2\right)}^{2} = 4 {x}^{2} - 8 x + 4$ so we need to subtract 1
$y = {\left(2 x - 2\right)}^{2} - 1$ which is better expressed as $y = 4 {\left(x - 1\right)}^{2} - 1$