Question

What is the vertex form of `y=5x^2-11`?

Answer 1

`y=5x^2-11`

Explanation:

Though the equation is in the standard form.
Its vertex form is the same.

The vertex form of the equation can be written as

`y=a(x-h)^2+k`

Here `h`is the x-coordinate of the vertex.
`k` is the y - coordinate of the vertex.

`a` is the co-efficient of `x^2`
Its vertex is `(0, -11)`
`a=5`
Then
`y=5(x-(0))^2-11`
`y=5x^2-11`