# What is the vertex form of #y=5x^2-11 #?

##### 1 Answer

May 30, 2016

#y=5x^2-11#

#### Explanation:

Though the equation is in the standard form.

Its vertex form is the same.

The vertex form of the equation can be written as

#y=a(x-h)^2+k#

Here

#a# is the co-efficient of#x^2#

Its vertex is#(0, -11)#

#a=5#

Then

#y=5(x-(0))^2-11#

#y=5x^2-11#