# What is the vertex form of y=5x^2-11 ?

May 30, 2016

$y = 5 {x}^{2} - 11$

#### Explanation:

Though the equation is in the standard form.
Its vertex form is the same.

The vertex form of the equation can be written as

$y = a {\left(x - h\right)}^{2} + k$

Here $h$is the x-coordinate of the vertex.
$k$ is the y - coordinate of the vertex.

$a$ is the co-efficient of ${x}^{2}$
Its vertex is $\left(0 , - 11\right)$
$a = 5$
Then
$y = 5 {\left(x - \left(0\right)\right)}^{2} - 11$
$y = 5 {x}^{2} - 11$