What is the vertex form of #y= 5x^2 + 22x + 8 #?

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Answer 1 · 2017-05-29T19:46:42

#"the vertex form of equation is "y=5(x+2.2)^2-16.2#

#y=5x^2+22x+8#

#"The vertex form is can be written as "y=a(x-h)^2-k#

#"where (h,k) is vertex coordinates"#

#y=5x^2+22x+color(red)(24.2-24.2)+8#

#y=5x^2+22x+24.2-16.2#

#y=5(color(green)(x^2+4.4x+4.84))-16.2#

#color(green)(x^2+4.4x+4.84)=(x+2.2)^2#

#y=5(x+2.2)^2-16.2#