What is the vertex form of #y= -5x^2-2x+24 #? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Binayaka C. Aug 21, 2017 The vertex form is # y = -5(x+0.2)^2+ 24.2 # Explanation: #y = -5x^2-2x+24 or y = -5(x^2+2/5x) +24 # or # y = -5(x^2+2/5x +1/25)+1/5 +24 # or # y = -5(x+1/5)^2+ 121/5 # or # y = -5(x+0.2)^2+ 24.2 #. Comparing with vertex form of equation # y = a(x-h)^2 +k ; (h,k)# being vertex , we find here #h= -0.2 , k =24.2# . So vertex is at # (-0.2,24.2)#. The vertex form is # y = -5(x+0.2)^2+ 24.2 # [Ans] Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1429 views around the world You can reuse this answer Creative Commons License