Question

What is the vertex form of `y= 6x^2+48x-54`?

Answer 1

`y+54=6x^2+48x->y+54=6(x^2+8x)`
`y+54+96=6(x^2+8x+16)->y+150=6(x+4)^2`

Explanation:

First add the 54 to the other side then factor out the 6. After that complete the square which is half the middle term square and add to both sides. But since there is a coefficient of 6 we multiply 16 by 6 before adding to the other side.