Question

What is the vertex form of `y=x^2+12x+36`?

Answer 1

Vertex form pf y = x^2 + 12x + 36.

Explanation:

y = (x + 6)^2
x-coordinate of vertex:
(x + 6) = 0--> x = - 6
y-coordinate of vertex: y = y(-6) = 36 - 72 + 36 = 0
Vertex form: y = (x + 6)^2