Question

What is the vertex form of `y=x^2/2 +10x + 22`?

Answer 1

The vertex form of `y=x^2/2+10x+22` is `y=(x+5)^2-3`

Explanation:

Let's start with the original equation:

`y=x^2/2+10x+22`

In order to turn this equation into vertex form, we're going to complete the square:

`y+(10/2)^2=x^2+10x+(10/2)^2+22`

`y+25=(x+5)^2+22`

`y=(x+5)^2-3`