# What is the vertex form of y=x^2/2 +10x + 22 ?

##### 1 Answer
Oct 24, 2017

The vertex form of $y = {x}^{2} / 2 + 10 x + 22$ is $y = {\left(x + 5\right)}^{2} - 3$

#### Explanation:

Let's start with the original equation:

$y = {x}^{2} / 2 + 10 x + 22$

In order to turn this equation into vertex form, we're going to complete the square:

$y + {\left(\frac{10}{2}\right)}^{2} = {x}^{2} + 10 x + {\left(\frac{10}{2}\right)}^{2} + 22$

$y + 25 = {\left(x + 5\right)}^{2} + 22$

$y = {\left(x + 5\right)}^{2} - 3$