# What is the vertex form of y=x^2/2 +10x + 22 ?

Oct 24, 2017

The vertex form of $y = {x}^{2} / 2 + 10 x + 22$ is $y = {\left(x + 5\right)}^{2} - 3$

#### Explanation:

$y = {x}^{2} / 2 + 10 x + 22$
$y + {\left(\frac{10}{2}\right)}^{2} = {x}^{2} + 10 x + {\left(\frac{10}{2}\right)}^{2} + 22$
$y + 25 = {\left(x + 5\right)}^{2} + 22$
$y = {\left(x + 5\right)}^{2} - 3$