# What is the vertex form of y=x^2 +216x + 432?

Oct 4, 2016

$y = {\left(x + 108\right)}^{2} - 11232$

#### Explanation:

1. Complete the square with ${x}^{2} + 216 x$
$y = {x}^{2} + 216 x + {\left(\frac{216}{2}\right)}^{2} - {\left(\frac{216}{2}\right)}^{2} + 432$
2. Form a perfect square
$y = {\left(x + 108\right)}^{2} - {\left(\frac{216}{2}\right)}^{2} + 432$
3. Simplify
$y = {\left(x + 108\right)}^{2} - 11664 + 432$
$= {\left(x + 108\right)}^{2} - 11232$