What is the vertex form of #y=x^2 +216x + 432#?
1 Answer
Oct 4, 2016
Explanation:
- Complete the square with
#x^2+216x#
#y=x^2+216x+(216/2)^2-(216/2)^2+432# - Form a perfect square
#y=(x+108)^2-(216/2)^2+432# - Simplify
#y=(x+108)^2-11664+432#
#=(x+108)^2-11232#
