# What is the vertex form of #y=x^2+2x+15#?

##### 1 Answer

Jan 10, 2016

#y=(x+1)^2+14#

#### Explanation:

Given _

#y=x^2+2x+15#

The vertex form of the equation is -

#y=a(x-h)^2+k#

If we know the values of

Find the vertex

#a=1#

#h= (-b)/(2a)=(-2)/(2 xx 1)=-1#

#k=(-1)^2+2(-1)+15=1-2+15=14#

Now substitute the values of

#y=(1)(x-(-1))^2+14#

#y=(x+1)^2+14#