What is the vertex form of #y=-x^2 -3#?
1 Answer
Jan 8, 2016
This is already in vertex form, it just doesn't look like it.
Vertex form is
#y=a(x-h)^2+k#
But here,
#a=-1#
#h=0#
#k=-3#
Which could be written as
#y=-1(x-0)^2+(-3)#
But, when simplified, it leaves
#y=-x^2-3#
Which means the parabola has a vertex at
graph{-x^2-3 [-13.82, 14.65, -12.04, 2.2]}
