# What is the vertex form of y=-x^2 -3?

Jan 8, 2016

This is already in vertex form, it just doesn't look like it.

Vertex form is

$y = a {\left(x - h\right)}^{2} + k$

But here,

$a = - 1$
$h = 0$
$k = - 3$

Which could be written as

$y = - 1 {\left(x - 0\right)}^{2} + \left(- 3\right)$

But, when simplified, it leaves

$y = - {x}^{2} - 3$

Which means the parabola has a vertex at $\left(0 , - 3\right)$ and opens downward.

graph{-x^2-3 [-13.82, 14.65, -12.04, 2.2]}