What is the vertex form of #y= x^2 - 3x + 2 #? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Konstantinos Michailidis Feb 26, 2016 It is #y=(x-3/2)^2-1/4# Explanation: The vertex form of a parabola is #y=a*(x-h)^2+k# hence #y=x^2-2*3/2*x+9/4+2-9/4=> y=(x-3/2)^2-1/4# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 2175 views around the world You can reuse this answer Creative Commons License