Question

What is the vertex form of `y= x^2+3x-25`?

Answer 1

`4y = (2x + 3)^2 -109`

Explanation:

The vertex form is `y=n(x-h)^2 + k` where `(h,k)` is the vertex.
It is found by completing the square.
`y = (x +3/2)^2 - 9/4 -25`
`y = (x + 3/2)^2 -109/4`
this can also be expressed as
`4y = (2x + 3)^2 -109`