# What is the vertex form of y= x^2 – 3x – 40?

${\left(x - \frac{3}{2}\right)}^{2} = y + \frac{169}{4} \text{ " }$the Vertex Form

#### Explanation:

From the given $y = {x}^{2} - 3 x - 40$ perform "Completing the square method#

$y = {x}^{2} - 3 x - 40$

We add and subtract $\frac{9}{4}$ to complete the square

$y = {x}^{2} - 3 x + \frac{9}{4} - \frac{9}{4} - 40$

$y = {\left(x - \frac{3}{2}\right)}^{2} - \frac{169}{4}$

$y + \frac{169}{4} = {\left(x - \frac{3}{2}\right)}^{2}$

${\left(x - \frac{3}{2}\right)}^{2} = y + \frac{169}{4} \text{ " }$the Vertex Form

God bless...I hope the explanation is useful..