# How do you find the vertex and intercepts for #y= -2x^2 + 12x - 13#?

##### 1 Answer

Jul 8, 2017

Vertex (3, 5)

#### Explanation:

x-coordinate of vertex:

y-coordinate of vertex:

y(3) = - 2(9) + 12(3) - 13 = - 18 + 36 - 13 = 5

Vertex (3, 5)

To find y-intercept, make x = 0 --> y-intercept = - 13.

To find the 2 intercept, make y = 0 and solve:

There are 2 x-intercepts (real roots):

graph{-2 x^2 + 12x - 13 [-20, 20, -10, 10]}