What is the vertex form of #y=x^2 - 4x + 14 #?

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Answer 1 · 2016-03-19T14:47:07

#y = 1(x-2)^2+10#

Complete the square to rearrange into vertex form:

#y = x^2-4x+14#

#=x^2-4x+4+10#

#=(x-2)^2+10#

#=1(x-2)^2+10#

The equation:

#y = 1(x-2)^2+10#

is in the form:

#y = a(x-h)^2+k#

which is the equation of a parabola with vertex at #(h,k) = (2,10)# and multiplier #1#.