# What is the vertex form of #y=x^2+4x+16#?

##### 1 Answer

#### Explanation:

The standard form of a quadratic equation is:

#y = ax^2 + bx + c#

The vertex form is :

For the given function

The x-coordinate of the vertex (h)

and the corresponding y-coordinate is found by substituting x =- 2 into the equation :

#rArr y = (- 2 )^2+4(- 2 ) + 16 = 4 - 8 + 16 = 12 #

the coordinates of the vertex are (- 2 , 12 ) = (h , k )

the vertex form of

# y = (x + 2 )^2 + 12 #

check:

#(x + 2 )^2 + 12 = x^2 + 4x +16#