# What is the vertex form of y=x^2-4x+3?

Dec 30, 2015

$y = {\left(x - 2\right)}^{2} - 1$

#### Explanation:

Use completing the square to get the equation into the form $y = a {\left(x + b\right)}^{2} + c$
In this case $a = 1$ and $b = \frac{- 4}{2} = - 2$
$c = - {b}^{2} + 3 = - 4 + 3 = - 1$
$y = {\left(x - 2\right)}^{2} - 1$

The vertex is $\left(2 , - 1\right)$