Question

What is the vertex form of `y=x^2-4x+3`?

Answer 1

`y = (x-2)^2 -1`

Explanation:

Use completing the square to get the equation into the form `y=a(x+b)^2 +c`
In this case `a = 1` and `b = (-4)/2 = -2`
`c = -b^2 +3 = -4 +3 = -1`
`y = (x-2)^2 -1`

The vertex is `(2, -1)`