What is the vertex form of #y= x^2 - 5x + 4 #?

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Answer 1 · 2016-02-26T10:41:09

Vertex form #(x-5/2)^2=y--9/4#

from the given #y=x^2-5x+4#
we complete the square

#y=x^2-5x+25/4-25/4+4#

#y=(x^2-5x+25/4)-25/4+16/4#

#y=(x-5/2)^2-9/4#

#y+9/4=(x-5/2)^2#

also

#(x-5/2)^2=y--9/4#

graph{y=x^2-5x+4[-20,20,-10,10]}

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