# What is the vertex form of y= x^2 + 6x + 36?

Mar 28, 2016

$y = {\left(x + 3\right)}^{2} + 27.$

#### Explanation:

x-coordinate of vertex:
$x = - \frac{b}{2 a} = - \frac{6}{2} = - 3$
y-coordinate of vertex:
y(-3) = 9 - 18 + 36 = 27
Vertex (-3, 27)
Vertex form: $y = {\left(x + 3\right)}^{2} + 27$.