# What is the vertex form of y= x^2 + 6x+8 ?

Apr 18, 2018

$y = {\left(x + 3\right)}^{2} - 1$

#### Explanation:

$y = {x}^{2} + 6 x + 8$

$y = {x}^{2} + 6 x + 9 - 1$

$y = {\left(x + 3\right)}^{2} - 1$

The vertex is $\left(- 3 , - 1\right)$