What is the vertex form of y = x^2+7x-1?

Aug 6, 2016

$y = {\left(x + \frac{7}{2}\right)}^{2} - \frac{53}{4}$

Explanation:

x-coordinate of vertex:
$x = - \frac{b}{2 a} = - \frac{7}{2}$
y-coordinate of vertex:
$y \left(- \frac{7}{2}\right) = \frac{49}{4} - \frac{49}{2} - 1 = - \frac{53}{4}$
$V e r t e x \left(- \frac{7}{2} , - \frac{53}{4}\right)$
Vertex form of y:
$y = {\left(x + \frac{7}{2}\right)}^{2} - \frac{53}{4}$