Question

What is the vertex form of `y= x^2 - 7x + 10`?

Answer 1

When given a quadratic of the form, `y=ax^2+bx+c`, the vertex form is `y=a(x+b/(2a))^2-b^2/(4a)+c`

Explanation:

For the given equation, `y= x^2 - 7x + 10`, `a = 1`, `b = -7`, and #c = 10.

Substitute these values into the vertex form, `y=a(x+b/(2a))^2-b^2/(4a)+c`:

`y=1(x+(-7)/(2(1)))^2-(-7)^2/(4(1))+10`

Simplify:

`y=1(x-7/2)^2-9/4`