# What is the vertex form of #y=x^2+8x+14 #?

##### 1 Answer

Jan 30, 2016

# y = (x + 4)^2 - 2#

#### Explanation:

the standard form of a parabola is

# y = ax^2 + bx + c# compare to

# y = x^2 + 8x + 14 # to obtain a = 1 , b= 8 and c = 14

The vertex form is :

# y =a (x - h )^2 + k # where (h , k ) are the coordinates of the vertex.

x-coord of vertex

#= - b/(2a) = -8/4 = - 2 # the y-coord =

#(-2)^2 + 8(-2) + 14 =8-16+ 14 = -2#

equation is :

in this question(see above ) a = 1