# What is the vertex form of y=x^2 +8x+15 ?

The equation in vertex form is , $y = {\left(x + 4\right)}^{2} - 1$
$y = {x}^{2} + 8 x + 15 = {\left(x + 4\right)}^{2} - 16 + 15 = {\left(x + 4\right)}^{2} - 1 \therefore$Vertex is at $\left(- 4 , - 1\right)$ graph{x^2+8x+15 [-10, 10, -5, 5]}[Ans]