# What is the vertex form of #y= (x + 2)(x - 6)#?

##### 1 Answer

May 14, 2016

#y = (x-2)^2-16#

or if you want it in exactly

#y = 1(x-2)^2+(-16)#

#### Explanation:

How did I get that?

Since we have factors

Then the vertical axis of symmetry must lie half way between these, making it the line

So we must have:

#y = (x-2)^2+c#

for some constant

Then putting

#(x+2)(x-6) = (2+2)(2-6) = 4*(-4) = -16#

So

The vertex of the parabola is at