Question

What is the vertex form of `y=x^2-x-72`?

Answer 1

`y=(x-1/2)^2-72 1/4`

Explanation:

Given

`y=x^2-x-72`

Find the Vertex

X-cordinate of the vertex

`x=(-b)/(2a)=(-(-1))/(2xx1)=1/2`
At `x=1/2; y=(1/2)^2-1/2-72=1/4-1/2-72=-72 1/4`

Vertex for of the quardratic equation is

`y=a(x-h)+k`

Where `h` is `x`cordinate and `k` is `y` coordinate
`a` is the coefficient of `x^2`

`h=1/2`
`k=-72 1/4`
`a=1`

Substitute these values in the formula

`y=(x-1/2)^2-72 1/4`

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