# What is the vertex form of #y=x^2-x-72 #?

##### 1 Answer

Jul 24, 2016

#y=(x-1/2)^2-72 1/4#

#### Explanation:

Given

#y=x^2-x-72#

Find the Vertex

X-cordinate of the vertex

#x=(-b)/(2a)=(-(-1))/(2xx1)=1/2#

At#x=1/2; y=(1/2)^2-1/2-72=1/4-1/2-72=-72 1/4#

Vertex for of the quardratic equation is

#y=a(x-h)+k#

Where

#h=1/2#

#k=-72 1/4#

#a=1#

Substitute these values in the formula

#y=(x-1/2)^2-72 1/4#