Question

What is the vertex form of `y= (x-4)(2x+2)-x^2+2x`?

Answer 1

`y = (x-7/2)^2 -111/4`

Explanation:

First simplify by multiplying out and grouping like terms together to get standard form.
`y =(2x^2 -8x +2x -8) -x^2 +2x`
`y = x^2 -7x -8`
Then the vertex form is
`y = (x-7/2)^2 -79/4 -8`
`y = (x-7/2)^2 -111/4`