# What is the vertex form of y= (x-5)(x+6)^2 - (x-5)^2 (x+6) ?

##### 1 Answer
Jan 12, 2016

y=$11 {\left(x + \frac{1}{2}\right)}^{2} - \frac{1331}{4}$

#### Explanation:

On simplification, the given equation would be y= (x-5)(x+6){x+6-(x-5)}.

=$11 \left({x}^{2} + x - 30\right)$. This can be converted to vertex form by completing the square.

= $11 \left({x}^{2} + x + \frac{1}{4} - \frac{1}{4} - 30\right)$

=$11 {\left(x + \frac{1}{2}\right)}^{2} - \frac{1331}{4}$