Question

What is the vertex form of `y= (x-5)(x+6)^2 - (x-5)^2 (x+6)`?

Answer 1

y=`11(x+1/2)^2 - 1331/4`

Explanation:

On simplification, the given equation would be y= (x-5)(x+6){x+6-(x-5)}.

=`11(x^2 +x-30)`. This can be converted to vertex form by completing the square.

= `11(x^2 +x +1/4 -1/4 -30)`

=`11(x+1/2)^2 - 1331/4`