What is the vertex of the parabola $y = 2 {(x + 4)}^{2} - 7$ $y=2(x+4)^2-7$ ?

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What is the vertex of the parabola $y = 2 {(x + 4)}^{2} - 7$ $y=2(x+4)^2-7$ ?

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Answer 1 · 2016-06-17T10:50:46

The vertex is $V = (- 4; - 7)$ $V=(-4;-7)$

Explanation:

If the quadratic function is in the form $f (x) = a {(x + b)}^{2} + c$ $f(x)=a(x+b)^2+c$ for real $a, b, c$ $a,b,c$ then its vertex has coordinates $V = (- b, c)$ $V=(-b,c)$

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What is the vertex of the parabola $y = 2 {(x + 4)}^{2} - 7$ $y=2(x+4)^2-7$ ?

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Science

Math

Humanities

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What is the vertex of the parabola y=2(x+4)^2-7y=2(x+4)2−7 y=2(x+4)^2-7?

1 Answer

Explanation:

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What is the vertex of the parabola $y = 2 {(x + 4)}^{2} - 7$ $y=2(x+4)^2-7$ ?