What is the vertex of the parabola  y=2(x+4)^2-7?

1 Answer
Jun 17, 2016

The vertex is V=(-4;-7)

Explanation:

If the quadratic function is in the form $f \left(x\right) = a {\left(x + b\right)}^{2} + c$ for real $a , b , c$ then its vertex has coordinates $V = \left(- b , c\right)$