# What is the vertex of the parabola y=x^2 -4?

Jul 12, 2017

$\left(0 , - 4\right)$

#### Explanation:

To find the vertex, we first need to find the axis of symmetry, which is

$x = - \frac{b}{2 a}$

In this case, we have $b = 0$ and $a = 1$, so

$x = - \frac{0}{2 \left(1\right)} = 0$

Our axis of symmetry is $0$. This is the $x$ value of the vertex. Now, to find the $y$ value, we need to plug this value of $x$ back into the equation.

$y = {x}^{2} - 4$

$y = {0}^{2} - 4$

$y = - 4$

So the $y$ coordinate of the vertex is $- 4$.

This means our vertex is $\left(0 , - 4\right)$.