# What is the vertex of the parabola #y=(x+5)^2+49#?

##### 1 Answer

Mar 27, 2016

(-5 , 49)

#### Explanation:

The vertex form of the parabola is

#y =a(x-h)^2 + k # where (h , k) are the coordinates of the vertex.

The function

# y = (x + 5)^2+ 49" is in this form "# and by comparison h = - 5 and k = 49

thus vertex = ( -5 , 49 )

graph{(x+5)^2+49 [-320, 320, -160, 160]}