# What is the vertex of the parabola y=(x+5)^2+49?

Mar 27, 2016

(-5 , 49)

#### Explanation:

The vertex form of the parabola is $y = a {\left(x - h\right)}^{2} + k$

where (h , k) are the coordinates of the vertex.

The function $y = {\left(x + 5\right)}^{2} + 49 \text{ is in this form }$

and by comparison h = - 5 and k = 49

thus vertex = ( -5 , 49 )
graph{(x+5)^2+49 [-320, 320, -160, 160]}