Question

What is the vertex of the parabola `y=(x+5)^2+49`?

Answer 1

(-5 , 49)

Explanation:

The vertex form of the parabola is `y =a(x-h)^2 + k`

where (h , k) are the coordinates of the vertex.

The function `y = (x + 5)^2+ 49" is in this form "`

and by comparison h = - 5 and k = 49

thus vertex = ( -5 , 49 )
graph{(x+5)^2+49 [-320, 320, -160, 160]}