What is the vertex of the parabola #y=(x-8)^2+7#?
1 Answer
Mar 1, 2016
(8,7)
Explanation:
The standard form of a parabola in vertex form is.
#y =a (x-h)^2 + k " where (h,k) are the coords of vertex "# the equation :
#y = (x-8)^2 + 7 " is in this form "# and by comparison vertex (h,k) = (8,7)
here is the graph of the parabola,showing the vertex.
graph{(x-8)^2+7 [-22.2, 22.18, -11.1, 11.1]}