# What is the vertex of this parabola x = (y - 2)^2 + 4?

$\left(4 , 2\right)$ i.e. $x = 4$, $y = 2$.
The axis of this parabola is parallel to the x-axis, with a minimum $x$ value when $\left(y - 2\right) = 0$, i.e. $y = 2$.