# What is the vertex of  y = (1/8)(x – 5)^2 - 3?

Jan 29, 2016

The vertex is $v \left(\frac{1}{20} , \frac{201}{3200}\right)$

#### Explanation:

f(x) = y=1/8(x–5)^2−3
$f \left(x\right) = \frac{1}{8} \left({x}^{2} - 10 x + 1\right)$
Now for any $f \left(x\right) = y = a {x}^{2} + b x + c \text{ }$ form of the equation
The vertex, $v \left(h , k\right)$
 h = -b/(2a); and k = f(h)
 h = 1/20; k = f(1/20) = 201/3200 ~~ .063
The vertex is $v \left(\frac{1}{20} , \frac{201}{3200}\right)$