Question

What is the vertex of `y=5x^2-30x+49`?

Answer 1

`x_("vertex")=3" "` I have left the determination of `y_("vertex")` for you to do (substitution).

Explanation:

Write as:`" "y=5(x^2-30/5x)+49`

`x_("vertex") = (-1/2)xx(-30/5) = +3`

To determine `y_("vertex")` substitute for `x` in the equation

I will let you do that.