# What is the vertex of y=5x^2-30x+49 ?

Mar 2, 2016

x_("vertex")=3" " I have left the determination of ${y}_{\text{vertex}}$ for you to do (substitution).

#### Explanation:

Write as:$\text{ } y = 5 \left({x}^{2} - \frac{30}{5} x\right) + 49$

${x}_{\text{vertex}} = \left(- \frac{1}{2}\right) \times \left(- \frac{30}{5}\right) = + 3$

To determine ${y}_{\text{vertex}}$ substitute for $x$ in the equation

I will let you do that.