# What is the vertex of  y= x^2 - 2x - 15?

Vertex is at $\left(1 , - 16\right)$
$y = {x}^{2} - 2 x - 15 \mathmr{and} y = {\left(x - 1\right)}^{2} - 16$ We know, equation of parabola in vertex form is $y = a {\left(x - h\right)}^{2} + k$ where $\left(h , k\right)$ is the vertex. So here the vertex is at $\left(1 , - 16\right)$ graph{x^2-2x-15 [-40, 40, -20, 20]}[Ans]