# What is the vertex of  y=x^2 - 3x + 2 ?

$V e r t e x \left(\frac{3}{2} , - \frac{1}{4}\right)$
$x = - \frac{b}{2 a} = \frac{3}{2}$
$y \left(\frac{3}{2}\right) = \left(\frac{9}{4}\right) - 3 \left(\frac{3}{2}\right) + 2 = \frac{9}{4} - \frac{9}{2} + 2 = - \frac{9}{4} + \frac{8}{4} = - \frac{1}{4}$
$V e r t e x \left(\frac{3}{2} , - \frac{1}{4}\right)$