# What is the volume of a liquid if 32.5 g if the liquid has a density of 0.852 g/mL?

Dec 3, 2015

Density, $\rho$, is mass per unit volume: $\frac{m}{V}$, where $m$ is mass and $V$ is volume.

#### Explanation:

We are given that $\rho$ $=$ $0.852 \cdot g \cdot m {L}^{- 1}$; further that we have a mass of $32.5$ $g$. So if we divide the mass by the density, we should reasonably get an answer in VOLUME.

So, $\frac{m a s s}{\rho}$ $=$ (32.5*cancel(g))/(0.852*cancel(g)*mL^(-1)) = ?? mL. Approx. $35 - 40$ $m L$.

The answer is in $m L$, a measure of volume, as required, because ${\left(\frac{1}{m L}\right)}^{-} 1$ $=$ $m L$.

Dec 3, 2015

38.145mL

#### Explanation:

Mass of liquid = 32.5g
Density = 0.852g/mL
Volume = ?

Sol:-
Density is defined as mass per unit volume, $D = \frac{m}{V}$
or we can write this formula as $V = \frac{m}{D}$

Putting the values in above formula;
$V = \frac{32.5 g}{0.852 \frac{g}{\text{mL}}}$ = 38.145mL