What torque would have to be applied to a rod with a length of #4 m# and a mass of #3 kg# to change its horizontal spin by a frequency of #2 Hz# over #2 s#?

1 Answer
Feb 18, 2016

Answer:

#L=24#

Explanation:

#alpha=L/I#
#"alpha: angular acceleration"#
#"L:torque"#
#"I=moment of inertia"#
#alpha =(Delta omega)/(Delta t)#
#alpha=2/2=1#
#1=L/I#
#L=I#
#L=1/12*m*l^2#
# "moment of inertia for a rod rotating around its center"#
#L=1/2*3*4^2=24#
#L=24#