Question

What torque would have to be applied to a rod with a length of `5 m` and a mass of `2 kg` to change its horizontal spin by a frequency of `24 Hz` over `8 s`?

Answer 1

`L=25pi`

Explanation:

`"torque is given by formula:"`
`L=alpha*I`
`"if rod spinning around of its center: " I=1/12*m*L^2`
`"else use " I=1/3*m*L^2`
`I=1/12*2*5^2`
`I=1/12*50`
`I=50/12`
`alpha=2pi*24/8=6pi`
`L=6pi*50/12`
`L=25pi`