What torque would have to be applied to a rod with a length of #5 m# and a mass of #2 kg# to change its horizontal spin by a frequency of #24 Hz# over #8 s#?

1 Answer
Feb 13, 2016

Answer:

#L=25pi#

Explanation:

#"torque is given by formula:"#
#L=alpha*I#
# "if rod spinning around of its center: " I=1/12*m*L^2 #
#"else use " I=1/3*m*L^2#
#I=1/12*2*5^2#
#I=1/12*50#
#I=50/12#
#alpha=2pi*24/8=6pi#
#L=6pi*50/12#
#L=25pi#