# What type of reaction is represented by the equation Zn(s)+H_2SO_4(aq)->ZnSO_4(aq)+H_2(g)?

Mar 5, 2016

The given reaction is a type of Displacement Reaction.

#### Explanation:

Displacement reaction is a kind of reaction in which a more reactive element displaces a less reactive element from its salt solution or a compound.
The reaction above is also a Single Displacement Reaction between a metal and an acid.
The comparison between reactivity is done using a reactivity series.
Reactivity series is shown below:-

As you see Zinc lies above Hydrogen in this series, so it is more reactive and hence it displaces hydrogen in ${H}_{2} S {O}_{4}$. This results in the formation of $Z n S {O}_{4}$ with the evolution of ${H}_{2}$ gas (you see this had been displaced by zinc).

Mar 5, 2016

It's a redox-reaction.

#### Explanation:

The zinc is oxidized from $Z n \to Z {n}^{2 +} + 2 {e}^{-}$
The hydrogen is reduced from $2 {H}^{+} + 2 {e}^{-} \to {H}_{2}$

${H}_{2} S {O}_{4} \left(a q\right)$ is actually $2 {H}^{+} + S {O}_{4}^{2 -}$
And
$Z n S {O}_{4} \left(a q\right)$ is actually $Z {n}^{2 +} + S {O}_{4}^{2 -}$

Since the sulfate ($S {O}_{4}^{2 +}$)-ion is unchanged (we call this a 'spectator' ion) we can leave it out of the equation:

The net equation is:
$Z n \left(s\right) + 2 {H}^{+} \left(a q\right) \to Z {n}^{2 +} \left(a q\right) + {H}_{2} \left(g\right)$