What volume of 0.10 M NaOHNaOH can be prepared from 250 mL of 0.30 M NaOHNaOH?
1 Answer
Explanation:
The thing to notice here is that the initial solution is
(0.30 color(red)(cancel(color(black)("M"))))/(0.10color(red)(cancel(color(black)("M")))) = 3
This tells you that the volume of the target solution must be
That is the case because when you dilute a solution, you decrease its concentration by increasing its volume while keeping the number of moles of solute constant.
http://acidsandbasesfordummieschem.weebly.com/molarity.html
This implies that when the concentration of a solution decreases by a factor, which is usually called dilution factor,
color(blue)(|bar(ul(color(white)(a/a)"DF" = V_"final"/V_"initial" = c_"initial"/c_"final"color(white)(a/a)|)))
You thus have
V_"final" = 3 xx "250 mL" = color(green)(|bar(ul(color(white)(a/a)color(black)("750 mL")color(white)(a/a)|)))
The answer is rounded to two sig figs.
So, you can decrease the concentration of