What volume of 4.00 M #H_2SO_4# is needed to prepare 500.0 mL of a solution that is 0.850 M in #H_2SO_4#?

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Answer 1 · 2018-07-11T05:29:06

Approx. #0.10*L#...

We use the definition of concentration....

#"concentration"="moles of solute"/"volume of solution"#...

And thus the END molar quantity we require is...

#500*mLxx10^-3*L*mL^-1xx0.850*mol*L^-1=0.425*mol#

And since this derives from a #4.00*mol*L^-1# concentration of sulfuric acid...for the volume....

We take the quotient...#(0.425*mol)/(4.00*mol*L^-1)~=0.106*L#...i.e. #106*mL#...

The acid should be added to water, and never vice versa...