# What volume of 4.00 M H_2SO_4 is needed to prepare 500.0 mL of a solution that is 0.850 M in H_2SO_4?

Jul 11, 2018

Approx. $0.10 \cdot L$...

#### Explanation:

We use the definition of concentration....

$\text{concentration"="moles of solute"/"volume of solution}$...

And thus the END molar quantity we require is...

$500 \cdot m L \times {10}^{-} 3 \cdot L \cdot m {L}^{-} 1 \times 0.850 \cdot m o l \cdot {L}^{-} 1 = 0.425 \cdot m o l$

And since this derives from a $4.00 \cdot m o l \cdot {L}^{-} 1$ concentration of sulfuric acid...for the volume....

We take the quotient...$\frac{0.425 \cdot m o l}{4.00 \cdot m o l \cdot {L}^{-} 1} \cong 0.106 \cdot L$...i.e. $106 \cdot m L$...

The acid should be added to water, and never vice versa...