# What volume of 5.0 M NaOH is required to make 100 mL 2.0 M NaOH?

May 2, 2016

$40 \cdot m L$ of $5.0 \cdot m o l \cdot {L}^{-} 1$ sodium hydoxide are required.

#### Explanation:

The $\text{concentration"xx"volume}$ gives answer in amount of substance.

Thus ${C}_{1} {V}_{1} = {C}_{2} {V}_{2}$, where ${C}_{1} , {V}_{1}$ are the initial concentrations, volume etc.

We need to find ${V}_{1}$ $=$ $\frac{\left[{C}_{1}\right] \left[{V}_{2}\right]}{\left[{C}_{2}\right]}$

$= \frac{2.0 \cdot m o l \cdot {L}^{-} 1 \times 0.100 \cdot L}{5.0 \cdot m o l \cdot {L}^{-} 1}$ $=$ ??*L=??*mL