# What volume of a 6.84M sodium bromide solution would be needed to make 588mL of a 1.84M solution by dilution?

Jul 29, 2016

The initial volume is $158 m L$

#### Explanation:

Whenever you are dealing with a dilution, (going from a higher concentration to a lower concentration), use the equation below:

Let's determine our known and unknown variables:

color(coral)("Knowns:"

• Initial Molarity
• Final Volume
• Final Molarity

color(magenta)("Unknowns:"

• Initial Volume

Next, we rearrange the equation to solve for ${V}_{1}$ by dividing by ${M}_{1}$ on both sides of the equation:

${V}_{1} = \frac{{M}_{2} \times {V}_{2}}{M} _ 1$

Plug in the known values and solve for your unknown:
${V}_{1} = \left(1.84 \cancel{\text{M"xx588mL)/(6.84cancel"M}}\right)$

Thus,

${V}_{1} = 158 m L$