# What volume of #"NH"_3# at STP is produced if #25.0 "g"# of #"N"_2# is reacted with an excess of #"H"_2# in the reaction #"N"_2 + 3"H"_2 -> 2"NH"_3#?

##### 1 Answer

Mar 16, 2016

#### Explanation:

Therefore,

#frac{25.0"g"}{28.0 "g/mol"} = 0.893 "mol"#

Each molecule of

Therefore, the 2 times the amount of

#2 xx 0.893 "mol" = 1.79 "mol"#

One mole of an ideal gas has a volume of

Therefore, the volume occupied by

#1.79 "mol" xx 22.4 "L/mol" = 40.0 "L"#

That's it. But bear in mind that you need to somehow remove the excess