# When 3.36 x 10^4 liters of oxygen reacts with propane, how many molecules of water are produced?

Mar 15, 2018

Perhaps you're referring to the combustion of propane,

$C {H}_{3} C {H}_{2} C {H}_{3} \left(l\right) + 5 {O}_{2} \left(g\right) \to 3 C {O}_{2} \left(g\right) + 4 {H}_{2} O \left(g\right)$

Generally, for gases at STP, we can assume that $1 \text{mol" approx 22.4"L}$ since other conditions aren't given.

Hence,

$3.36 \cdot {10}^{4} \text{L" * "mol"/(22.4"L") * (4H_2O)/(5O_2) * (6.02*10^23"molecules")/"mol} \approx 7.22 \cdot {10}^{26}$

molecules of water vapor are produced stoichiometrically.