# When working in decimal radians, how do you find x given 65^0 = sin^-1 x ? ?

x = $\sin {65}^{0}$ = sin $65 \cdot \frac{\pi}{180}$ = sin$13 \frac{\pi}{36}$
$\pi$ rad = ${180}^{0}$
Also $\theta$ =${\sin}^{-} 1$ x $\implies$ x = sin$\theta$