# Write the balanced chemical equation for the following reactions. Then change each reaction to ionic form; finally to net ionic equations.? a. NaOH(aq) + HCl(aq) = b. Pb(C2H3O2)2(aq) + K2SO4(aq) = c. FeSO4(aq) + (NH4)2S(aq) = d. NaCl(aq) + KOH(aq) =

Mar 23, 2017

a.) $N a O H \left(a q\right) + H C l \left(a q\right) \rightarrow N a C l \left(a q\right) + {H}_{2} O \left(l\right)$

#### Explanation:

And the net ionic equation is simply the protonolysis rxn:

$H {O}^{-} + {H}^{+} \rightarrow {H}_{2} O \left(l\right)$, alternatively,

$H {O}^{-} + {H}_{3} {O}^{+} \rightarrow 2 {H}_{2} O \left(l\right)$

b.)Pb(OAc)_2(aq) + K_2SO_4(aq) rarr PbSO_4(s)darr + 2K^(+)""^(-)OAc(aq)

And the net ionic equation:

$P {b}^{2 +} + S {O}_{4}^{2 -} \rightarrow P b S {O}_{4} \left(s\right) \downarrow$

c.)FeSO_4(aq) + (NH_4)_2S(aq) rarr FeS(s)darr + (NH_4)_2S(aq)

And the net ionic equation:

$F {e}^{2 +} + {S}^{2 -} \rightarrow F e S \left(s\right) \downarrow$

d.)NaCl(aq) + KOH(aq) rightleftharpoons NaOH(aq) + KCl(aq)

For this last, there is NO macroscopic chemical change.