#y=cot^-1(-sqrt3)# Find the exact value of y?

Find the exact value of y. Do not use a calculator.

1 Answer
Feb 12, 2018

The answer is #y=(5pi)/6+pik# where #k# is any integer.

Explanation:

#y=cot^-1(-sqrt3)#

#cot(y)=cancel(cot)(cancel(cot^-1)(-sqrt3))#

#cot(y)=-sqrt3#

To make the problem a bit easier to visualize, I'll convert #cot# to #tan# by raising both sides of the equation to the power of #-1#.

#(cot(y))^-1=(-sqrt3)^-1#

#1/cot(y)=1/sqrt3#

#tan(y)=1/(-sqrt3)="opposite"/"adjacent"#

We can now construct a diagram:

https://www.desmos.com/calculator

When you divide all the side lengths in this triangle by #2#, you get a familiar looking triangle:

https://www.desmos.com/calculator

A triangle with the side length ratio #1/2:sqrt3/2:1# is a #30^@:60^@:90^@# triangle. That means that our reference angle is #30^@#.

Since the horizontal side length is negative, that means that the actual angle is the supplement of #30^@#, which is #150^@#.

The calculation would remain the same after any rotation of #180^@# degrees, so you can express the full answer as #150^@+180k^@# to represent the original answer and any #180^@# rotation.

In radians, this is #(5pi)/6+pik#.